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Python program to check if a year is a leap year or not
Web• My database can only store ages in terms of days alive, not years. • Write a Python program that will have a variable set to a person's age. It will then print out the following statement: Hello, you have been alive for days. • Assume every year has 365 days. No leap years. 24 Image Credit: WebTo check if a year is a leap year in Python, you can use this function: def is_leap(year): return year % 4 == 0 and (year % 100 != 0 or year % 400 == 0) Here are some example calls … high ptt result
Noob level leap year program. Don´t know how to solve it.
WebYou should follow the following steps to determine whether a year is a leap year or not. If a year is evenly divisible by 4 means having no remainder then go to next step. If it is not divisible by 4. It is not a leap year. For example: 1997 is not a leap year. If a year is divisible by 4, but not by 100. For example: 2012, it is a leap year. WebNov 11, 2024 · Since 2000 is a century year, it should be divisible by 400 to be a Leap Year. Code: year = 2100 if ( (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0)): … WebMay 5, 2024 · To determine whether a year is a leap year, follow these steps: If the year is evenly divisible by 4, go to step 2. Otherwise, go to step 5. If the year is evenly divisible by 100, go to step 3. Otherwise, go to step 4. If the year is evenly divisible by 400, go to step 4. Otherwise, go to step 5. The year is a leap year (it has 366 days). how many bullets does a magazine hold